Quantifying the Relative GHE for Various Planets
I decided to have some fun with a thought exercise to respond to claims I've been seeing about a paper published a few years ago by Robert Holmes. What I'm going to do below doesn't technically "predict" temperatures on other planets but it does show a simple model that explains why surface temperatures differ on planets in moons given both ASR and the GHE. In a previous post I debunked a silly paper from Holmes that claimed to be able to calculate the 1-bar temperatures of a planet knowing only the ratio of the TSI values for the two planets and the 1-bar T for the second planet. Holmes' used the following equation.
I showed that this equation doesn't work because it ignores both the GHE and albedo. It gives the superficial appearance of working if you calculate 1-bar T of Earth from Venus and vice versa, since Venus has both a strong albedo and GHE. But even then it only "works" if you use 340 K for Venus' 1-bar T, and NASA currently reports the 1-bar T for Venus to be 360K. And this formula doesn't work for any of the possible calculations involving Titan at all, so it has at best a 67% failure rate (if you accept 340 K for Venus). One thing I thought was interesting, though, is that if you use ASR instead of TSI, the results were still wrong, but they were wrong in such a way that indicated the relative strength of the GHE on these planets. So I decided to play around to see if I quantify a factor that would show the strength of the GHE using surface temperatures of Venus, Titan, and Earth. In my last post I derived the following formula and showed that it actually works for predicting effective temperature (Teff) values (which is a rather trivial point).
This works for Teff, but if we use surface temperature (Ts), we will get the wrong answer because the strength of the GHE is different in each planet. For instance (see chart below for calculations),
- Te = ∜rASR*Tv = 830 K, which is 2.88x the actual Te of 288 K.
- Te = ∜rASR*Tt = 283 K, which is 0.98x the actual Te of 288 K.
- Tv = ∜rASR*Te = 256 K, which is 0.35x the actual Tv of 737 K.
- Tv = ∜rASR*Tt = 251 K, which is 0.34x the actual Tv of 737 K.
- Tt = ∜rASR*Tv = 276 K, which is 2.93x the actual Tt of 94 K.
- Tt = ∜rASR*Te = 96 K, which is 1.02x the actual Tt of 94 K.
The factors in bold above are not accidental. We can actually show exactly why they have these values. These factors exist because on these planets not all the energy emitted from the surface (Fs) escapes to space, which is what is called a "greenhouse effect." We can quantify this as ε = ASR/Fs. So the factors above are actually the fourth root of ratio of the ε = ASR/Fs for the two planets. This is pretty easy to show. If we use Ts values, then we can use the following simple model:
- Earth: 240.2 Wm^-2 / 390.1 Wm^-2 = 0.62
- Venus: 150 Wm^-2 / 16730 Wm^-2 = 0.009
- Titan: 2.9 Wm^-2 / 4.4 Wm^-2 = 0.66
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